[EpiData-list] Re: Ranked variable questions

epidata-list at lists.umanitoba.ca epidata-list at lists.umanitoba.ca
Sun Aug 26 15:40:10 CDT 2007

```You are right Jamie - a response of 1 was given for most imporant. I
will try using your v1=10-v1 and then the method Jens suggests.

thank you very much to both you and Jens for your help

Christine

Christine Roseveare
Analyst
Regional Public Health
570 9194
027 495 9671

>>> <epidata-list at lists.umanitoba.ca> 24/08/2007 1:33 p.m. >>>
An important question is whether a response of 1 most important or
least
important?
If 1 is most important, then make the default value 11 and not zero.

I would just do:

describe v1-v25

and scan the medians to find those with the lowest median (if 1 is most

important and default is 11) or highest median (10 is most important
and
default is 0). Items that are infrequently ranked will have a median
equal to the default. Items most frequently ranked will have a median
that is based mostly on ranks.

I haven't thought about the formal statistical analysis here, but
you'll
get a pretty good assessment.

Jens approach works very well when the most important response is 10.
If
most important is 1, then you can also do this:

v1 = 10-v1
v2 = 10- v2
etc
and use aggregate.

jamie
> Christine wrote:
> I have been asked to set up a database for a questionnaire that has
> already been written. I was going to set it up in epidata but my
> problem is how to deal witha question that asks people to rank
> options. The question gives a list of topics and asks the person
> filling in the  questionnaire to rank them from 1-10 in order of
> importance.
>
Jens wrote:
> I suggest to do the following:
> For each question (say 25 different themes) enter the priority the
> person gave to that issue.
> setup the qes:
> v1 item1 ..... ##
> v2 item2 ..... ##
> etc
> v25 text for item 25 ##
>
> in chk make the defaultvalue 0:
> before file
>   DEFAULTVALUE v1-v25 0
> end
>
> Then in analysis after entering the data: (say you had the 25
variables)
> aggregate /sum="v1,v2,v3,v4,v5"
> aggregate /sum="v6,v7,v8,v9,v10"   etc
>
> * the tables will show the sum of the variables, that is the overall

> ranking sum.
>

--
The information contained in this email and
any attachments is confidential and may be
legally privileged. If you have received this
message in error, please notify the sender
immediately and remove all copies of the message,
including any attachments.  Any views or
opinions expressed in this email (unless
otherwise stated) may not represent those of
Hutt Valley DHB.
Thank you.
** Disclaimer added by HVDHB **

```